Unpacking a hex value

[Chris Liechti]

Matthew Diephouse <fokke_wulf at hotmail.com> wrote in 
news:3CE5BD65.3000908 at hotmail.com:

> The code is very much like the Perl code I submitted. It is within a 
> subroutine.
> 
> def hex2bin(input)
>       output = hex( input )
>       output = pack("!l", output)
>       ...

if you want to convert a number to a string containing the binary 
represenation of the number try it without hex():

def hex2bin(inp)
     output = pack("!l", inp)
    	...

hex() in python converts number->string. if the input above is a string 
with hexdigits use int() instead:
     output = pack("!l", int(inp,16))
or if you need to cut away '0x'
     output = pack("!l", int(inp[2:],16))

chris

>  From this, I get the error "required argument is not an integer", as 
> previously stated. There's no other info in the Traceback that's 
> important. I've tried wrapping output with a call to the int() function, 
> but that doesn't work either.
> 

-- 
Chris <cliechti at gmx.net>