Proposal: min(None, x) and max(None, x) return x

[Chad Netzer]

On Friday 22 November 2002 14:57, Alex Martelli wrote:

> perhaps a slightly better expression of the same idea might be...
>
> _xMax = []
> for -whatever-:
>   -big calculation leading to a value of x-
>   _xMax = [max([x]+_xMax)]
>   xMax = _xMax[0]

Thanks.  I knew if I posted this, someone would follow up with an improved 
way of doing it (I didn't like the .append() myself, and overlooked list 
concatenation).   Note that I put the 'xMax' assignment in the loop (assuming 
that's what the original poster required); otherwise you can avoid typing 
'_xMax':

xMax = []
for -whatever-:
  -big calculation leading to a value of x-
  xMax = [max([x]+xMax)]
xMax = xMax[0]


-- 
Bay Area Python Interest Group - http://www.baypiggies.net/

Chad Netzer
cnetzer at mail.arc.nasa.gov