*args and **kwargs

[Wojtek Walczak]

Dnia Wed, 27 Nov 2002 18:08:58 GMT, Dan napisał(a):
> thanks for the answer specifically for "args".  Still I don't quite
> understand the Python syntax.
> 
> *something = encapsulate into a set   ??
> **something = encapsulate into a Dictionary??
Yes, but only when defining a function. 
You can call a function in two ways (depends on a way it was defined):

def first(**a):
   print "\n".join([ "%s==%s" % (k,v) for k,v in a.items()])

first(a="b",b="c",c="d")


def second(a):
   print "\n".join([ "%s==%s" % (k,v) for k,v in a.items()])

second({"a":"b", "b":"c", "c":"d"})

In first case you know, that you need to pass a dictionary from
function's declaration (seeing **a just tells you that). In second case, 
you don't, you need to take a look at code or documentation. 
Maybe not at all, but, for sure, in some way that strange construction
is about readability.

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