httplib 'getaddrinfo failed'

Gordon Williams g_will at cyberus.ca
Fri Sep 20 19:50:01 CEST 2002


Hi All,

I recently got a DSL line to connect to the internet and my code is now
broken.  Could this be due to the DSL being different from a dialup
connection?

I'm using python 2.2 on W2000.

This is the traceback from the 2.2 httplib:


Traceback (most recent call last):
  File "G:\Python Files\Mutual Fund Updater\GetPrice.py", line 103, in ?
    f = u.open(url)
  File "G:\PROGRA~1\PYTHON22\lib\urllib.py", line 178, in open
    return getattr(self, name)(url)
  File "G:\PROGRA~1\PYTHON22\lib\urllib.py", line 288, in open_http
    h.putrequest('GET', selector)
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 452, in putrequest
    self.send(str)
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 394, in send
    self.connect()
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 362, in connect
    for res in socket.getaddrinfo(self.host, self.port, 0,
socket.SOCK_STREAM):
IOError: [Errno socket error] (2, 'getaddrinfo failed')


This is the traceback from the httplib in CVS that I got today.

Traceback (most recent call last):
  File "G:\Python Files\Mutual Fund Updater\GetPrice.py", line 103, in ?
    f = u.open(url)
  File "G:\PROGRA~1\PYTHON22\lib\urllib.py", line 178, in open
    return getattr(self, name)(url)
  File "G:\PROGRA~1\PYTHON22\lib\urllib.py", line 292, in open_http
    h.endheaders()
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 695, in endheaders
    self._send_output()
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 581, in _send_output
    self.send(msg)
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 548, in send
    self.connect()
  File "G:\PROGRA~1\PYTHON22\lib\httplib.py", line 516, in connect
    socket.SOCK_STREAM):
IOError: [Errno socket error] (2, 'getaddrinfo failed')


Same problem.  Any ideas?  I'm using Sympatico high speed edition which was
developed by Efficient Networks Inc. - if that is any help.

Regards,

Gordon Williams





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