isFloat: Without Exception-Handling
Steve Holden
sholden at holdenweb.com
Wed Sep 18 12:47:40 EDT 2002
"Rajarshi Guha" <rajarshi at presidency.com> wrote in message
news:pan.2002.09.18.11.40.50.766802.29524 at presidency.com...
> On Wed, 18 Sep 2002 11:41:47 -0400, Thomas Guettler wrote:
>
> > Hi!
> >
> > Is there a way to write the following method without using exceptions?
> >
> > def isFloat(string):
> > is_float=1
> > try:
> > float(string)
> > except:
> > is_float=0
> > return is_float
> >
> > print isFloat("asdf") # --> 0
> > print isFloat("0.1") # --> 1
>
>
> def isFloat(string):
> if type(string) == type(1.0):
> return 1
> else
> return 0
>
> This should do what you want without exceptions
I doubt that VERY much. Please test your code before submitting, or ensure
you note it wasn't tested ...
>>> def isFloat(s):
... if type(s) == type(1.0):
... return 1
... else:
... return 0
...
>>> isFloat("banana")
0
>>> isFloat("1.2")
0
Also note that, were your test the right one, it would be much more concise
to write the function as
def isFloat(s):
return type(s) == type(1.0)
regards
-----------------------------------------------------------------------
Steve Holden http://www.holdenweb.com/
Python Web Programming http://pydish.holdenweb.com/pwp/
Previous .sig file retired to www.homeforoldsigs.com
-----------------------------------------------------------------------
More information about the Python-list
mailing list