list problem

Duncan Booth duncan at
Tue Sep 24 11:07:31 CEST 2002

Thorsten Kampe <thorsten at> wrote in news:amp6i1$7n9bi$1 at ID-

> * Anthony Tuininga
>> If you have list comprehensions available, use
>> [b for a in x for b in a]
> What about:
> reduce(lambda x, y: x + y, a) ?

If you are going to use reduce, then you would be better off writing:

   import operator
   reduce(operator.add, x)

Duncan Booth                                             duncan at
int month(char *p){return(124864/((p[0]+p[1]-p[2]&0x1f)+1)%12)["\5\x8\3"
"\6\7\xb\1\x9\xa\2\0\4"];} // Who said my code was obscure?

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