How to split string in equally long parts

[Alexander Schmolck]

Carsten Gaebler <news at snakefarm.org> writes:

> Heiko Henkelmann wrote:
> > I need to split a string into an array of equally long substrings, like
> > e.g.:
> > 
> > '1234567890'   -> ['12', '34','56','78','90']
> > 
> > What is the most efficient way to do this?
> 
> I don't know how efficient it is but this is what came to my mind:
> 
> import re
> filter(None, re.split('(.{2})', '1234567890'))
> 
> cg.
> 

why not just:

>>> import re
>>> re.findall('..', '123456')
['12', '34', '56']


alex