Why doesn't __call__ lead to infinite recursion?
patrick at novaroot.com
Fri Aug 15 21:58:55 CEST 2003
def foo(): pass
foo is a function
foo is a callable object
foo has method __call__ defined
foo.__call__ is a function
foo.__call__ is a callable object
foo.__call__ has method __call__ defined
foo.__call__.__call__ is a function...
This seems to go on forever. How does calling foo() not lead to
an infinite loop while trying to execute?
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