abstraction of the column names (classes)
wiebke.paetzold at mplusr.de
Wed Aug 6 10:40:43 CEST 2003
On 5 Aug 2003 14:00:23 -0700, p-abel at t-online.de (Peter Abel) wrote:
>Wiebke Pätzold <wiebke.paetzold at mplusr.de> wrote in message news:<h29viv0b74ib3tc1g7eem3eo26fsjv93bj at 4ax.com>...
>> Hi all!
>> I create a database that contains a table. 'Nachname' is one of 13
>> column names. This program can search for
>> a special letter. In my example it is 'ra'. and the search takes place
>> in 'Nachname'. 'ra' takes place within a word. This is solved with
>> regular expression. So that I can limit my search.
>> For example: I can search for 'ra' and it is not relevant wich letters
>> follow or wich letters are in front of 'ra'.
>> Now I want to abstract the column name 'Nachname'. So I search in an
>> unknown column. Only the user of the program should determine in wich
>> class the search takes place. This input should happen in the view
>> lines of testing the class.
>> My task is it to change the program that a abstraction of the column
>> names takes place.
>> Please give me a detailed answer. If it is possible the changed
>> program because I am very new in Python and I am orientationless.
>> This is the program
>> import sys
>> import Mk4py
>> import re
>> db = Mk4py.storage("c:\\datafile.mk",1)
>> vw = db.view("people")
>> class PatternFilter:
>> def __init__(self, pattern):
>> self.pattern = re.compile(pattern)
>> def __call__(self, row):
>> nachname = row.Nachname
>> except AttributeError:
>> return 0
>> return self.pattern.search(nachname)is not None
>> vf = vw.filter(PatternFilter("ra.*"))
>> for r in vf:
>> print vw[r.index].Nachname
>RegEx are really great and there are a lot of problems you can
>only solve with them. But if I understand you right your problem
>is to find a string where a substring is to be in, the simple
>string operation does the work:
>if String.find(substring) > -1:
>**find** will give you the position in String where substring
>will occure the 1rst time and -1 if substring doesn't occur.
>>>> nameList=['Meyer', 'Maxon', 'Johnson', 'Mueller']
>>>> for name in nameList:
>... if name.find('er')>-1:
>... print name
>So if you can get your columns contents in **ColumnList**
>and your searchpattern in **SearchPattern** so the following
>function could do the work:
> for n in ColumnList:
> if n.find(SearchPattern) > -1:
> return foundList
there is another problem too. I have NOT a string. Ihave a TABLE.
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