Misleading description of [i:j:k] slicing?

[Michael Hudson]

Raoul Gough <RaoulGough at yahoo.co.uk> writes:

> Michael Hudson <mwh at python.net> writes:
> 
> > Raoul Gough <RaoulGough at yahoo.co.uk> writes:
> >> Seems to me that "0 <= n < abs(i-j)" is wrong, since the range of n
> >> gets multiplied by k. 
> >
> > How about "0 <= n < abs(k*(i-j))"?  But you're right, what's there is
> > a bit wrong.  It's surprisingly hard to get this written down well.
> > The idea's not that hard, but a terse explanation is surprisingly
> > hard (when you start omitting values it gets even more fun!).
> >
> > Please submit a patch (assign it to me if you like -- the above
> > passage is my fault).
> 
> I've submitted a bug to the sourceforge tracker for Python, but
> couldn't see how to assign it to anyone. Bug number is 792656, hope
> this is what you meant.

I've assigned it to myself now, cheers.

Cheers,
mwh

-- 
  I'd certainly be shocked to discover a consensus.  ;-)
                                      -- Aahz Maruch, comp.lang.python