2.3 list reverse() bug?
Paul Rubin
http
Thu Dec 25 06:12:02 EST 2003
cartermark46 at ukmail.com (Mark Carter) writes:
> >>> d1 = [1,2]
> >>> d2 = d1
> >>> d2.reverse()
> >>> print d1 #note: d1, not d2
> [2, 1]
>
> Surely that can't be right: d1 should still be [1,2]. If it is
> "right", then I expect that many people are in for a suprise.
It's correct. d1 and d2 are the same list, and list.reverse reverses
in place. If you want d1 and d2 to be two separate lists, try
d1 = [1,2]
d2 = d1[:] # makes a copy of d1
d2.reverse()
print d1
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