List comprehension confusion...

[Lulu of the Lotus-Eaters]

Andrew Dalke <adalke at mindspring.com> wrote previously:
|get the "some_field" attribute of all elements in a list
|results = [term.some_field for term in data]

Just to throw flame on the fire, I am one of the odd people who find map
quite readable too:

  result = map(lambda t: t.some_field, data)

Yours, Lulu...

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