datetime module: iso date *input* needed

[Dale Strickland-Clark]

george young <gry at ll.mit.edu> wrote:

>[python 2.3a1, linux]
>I'm using the 2.3a datetime module.  The datetime.isoformat() works nicely:
>  >>> import datetime
>  >>> d=datetime.datetime.now()
>  >>> d
>  datetime.datetime(2003, 1, 30, 17, 48, 7, 848769)
>  >> d.isoformat()
>  '2003-01-30T17:48:07.848769'
>
>but now I need a way to make a datetime object from a date in iso format.
>I can't find a function in datetime to do this, e.g. something like:
>  d=datetime.datetime.parse_iso('2003-01-30T17:48:07.848769')
>
>I thought about using the time module strptime function, but it doesn't do
>fractions of a second.  I used to move date/times between python and postgres as
>epoch integers, but I hope to change to a human-readable format for better
>debugging.  
>
>I'm sure I could do this somehow with mx.DateTime, but if the datetime module
>is going to be the new standard, I would like to use it in my new code...
>
>-- George

A bit of a sledgehammer but what about:

>>> import re
>>> t = '2003-01-30T17:48:07.848769'
>>> p = re.compile('[.:T-]')
>>> isobits = [int(s) for s in p.split(t)]
>>> isobits
[2003, 1, 30, 17, 48, 7, 848769]
>>> apply(datetime.datetime, isobits)

I assume this will work but I don't have 2.3a installed so no datetime
module to play with.

--
Dale Strickland-Clark
Riverhall Systems Ltd