ykingma at accessforall.nl
Fri Jan 17 19:51:32 CET 2003
> On Thu, 16 Jan 2003 22:28:05 +0100, Ype Kingma <ykingma at accessforall.nl>
>>> Some code I "exec" throws a TypeError exception. I want it to throw this
>>> exception but want to be able to catch this along with the others which
>>> are in fact being caught by the try/except block.
>>> The specific TypeError in this case is caused by a module-defined
>>> function being called with the incorrect number of arguments. Again,
>>> I want to catch this exception. The problem is, this exception, unlike
>>> the others, is not being caught/handled by my try/except block.
>>How do you know it is thrown?
> Upon execution of the Python script, the standard exception printout
> occurs at this location, denoting exactly what the error is and
> halting execution of the script.
> Traceback (most recent call last):
> File "C:\test.py", line 21, in ?
> for line, expecting in lines:
> TypeError: function takes exactly 0 arguments (1 given)
> Where, given my code it should have shown (and continued execution) :
I don't follow this '(and continued execution)'.
> ('Foo() takes exactly 0 arguments (1 given)',)
But the lines read (from your first post):
lines = [
('foo = MyModule.Something()',1),
Where is this Foo() call?
Could you isolate the problem in some minimal bits of code
and post all that code?
email at xs4all.nl
More information about the Python-list