# Calculating Year, Month and Day of Life

hokiegal99 hokiegal99 at hotmail.com
Sat Jul 5 20:24:42 CEST 2003

```hokiegal99 wrote:
> Hello,
>
> I am a funeral director trying to write a small program that calculates
> the number of years, months and days a person has lived by entering the
> year, month and day of their birth. This is what I have so far:
>
> #---------------------
> from time import *
> local = localtime()
>
> print "Enter the year of birth:"; y = input()
> print "Enter the month of birth:"; m = input()
> print "Enter the day of birth:"; d = input()
>
> age = y,m,d
> print age
> print local
> #----------------------
>
> The output looks similiar to this:
> (1934, 2, 7)
> (2003, 7, 5, 13, 20, 0, 5, 186, 1)
>
> My problem is that localtime is a list of 9 integers while age is a list
> of 3 integers. Is it possible to make localtime() only return the first
> 3 integers? If so, how would I then do calculations on the two lists'
> individual parts? For example, how would I instruct localtime() to
> subtract the first integer from age's list from the first intger in its
> own list (2003 - 1934)?
>
> Also, I am new to python, but I like it a lot and have picked it up
> quickly. If my approach to this solving this problem is completely
> wrong, please point me in the right direction.
>
>

Sorry to respond to my own post, but I answered the first part of my
question by experimenting a bit. I pulled the first 3 integers from
localtime() like this:

local = localtime()
print local[:3]
(2003, 7, 5)

```