file.close()
Bryan
belred1 at yahoo.com
Thu Jul 24 01:20:15 EDT 2003
>
> If you need 50 open files, you almost certainly want to have a way of
> organizing them. Probably they'll be in a list or dictionary. So, if
> they're in a list, for example, you can do this:
>
>
> filelist = []
> try:
> filelist.append(open(filename[0]))
> filelist.append(open(filename[1]))
> ...
> do_something(filelist)
> finally:
> for f in filelist:
> f.close()
>
erik, carl... thanks... this is exactly what i was looking for
bryan
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