# Newbie: changing an attribute of objects in a list

Steven Taschuk staschuk at telusplanet.net
Thu Jun 12 19:15:47 CEST 2003

```Quoth Ben Simuyandi:
> Example objects in a list [a,b,...,i]:
[...]

Thanks!

There's two things I don't understand in your examples.  One in
each, tidily enough.

In the first example, where all items start with .order == 1 and
the output is supposed to be

a.age == 100    a.order == 9
b.age == 200    b.order == 6
c.age == 300    c.order == 5
d.age == 400    d.order == 4
e.age == 500    e.order == 3
f.age == 600    f.order == 2
g.age == 50     g.order == 9
h.age == 700    h.order == 1
i.age == 150    i.order == 7

why do a and g get the same .order?  I'd expected that we want
g.order == 9 and a.order == 8.

[...]
d.age == 400    d.order == 4
e.age == 500    e.order == 4
f.age == 600    f.order == 5
g.age == 50     g.order == 6
h.age == 700    h.order == 7
i.age == 150    i.order == 8

and are to produce

[...]
d.age == 400    d.order == 4
e.age == 500    e.order == 5
f.age == 600    f.order == 6
g.age == 50     g.order == 7
h.age == 700    h.order == 8
i.age == 150    i.order == 9

Again the handling of g puzzles me.  Here's my thinking:

1) d and e both have order 4; since d.age < e.age, we let d have
order 4 and bump e up to order 5.

2) Then e and f both have order 5; since e.age < f.age, we let e
have order 5 and bump f up to order 6.

3) Then f and g both have order 6.  In the example posted, f gets
order 6 and g gets bumped up to order 7.  But f.age > g.age, so I
expected g to take precedence for order 6.

What's going on here?  I'm baffled.

--
Steven Taschuk                               staschuk at telusplanet.net
"[T]rue greatness is when your name is like ampere, watt, and fourier
-- when it's spelled with a lower case letter."      -- R.W. Hamming

```