handling errors

ataraxia2500 messageboardfan1 at yahoo.com
Thu Jun 5 02:38:15 CEST 2003


I got that little piece of code on a tutorial. I want to add an error
handling to the print_menu function so that if the user enter strings
instead of int the program doesn't crash but I couldn't make it. I tried to
add: "except ValueError:
        print "That was not a number.""
at the end but it didn't do anything. any idea how I should use it?

thanx in advance

def print_menu():
    print '1. Print Phone Numbers'
    print '2. Add a Phone Number'
    print '3. Remove a Phone Number'
    print '4. Lookup a Phone Number'
    print '5. Quit'
    print
numbers = {}
menu_choice = 0
print_menu()
while menu_choice != 5:
    menu_choice = input("Type in a number (1-5):")
    if menu_choice == 1:
        print "Telephone Numbers:"
        for x in numbers.keys():
            print "Name: ",x," \tNumber: ",numbers[x]
        print
    elif menu_choice == 2:
        print "Add Name and Number"
        name = raw_input("Name:")
        phone = raw_input("Number:")
        numbers[name] = phone
    elif menu_choice == 3:
        print "Remove Name and Number"
        name = raw_input("Name:")
        if numbers.has_key(name):
            del numbers[name]
        else:
            print name," was not found"
    elif menu_choice == 4:
        print "Lookup Number"
        name = raw_input("Name:")
        if numbers.has_key(name):
            print "The number is",numbers[name]
        else:
            print name," was not found"
    elif menu_choice != 5:
        print_menu()




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