Newbie question about function return values
cnetzer at mail.arc.nasa.gov
Sat Mar 15 01:50:41 CET 2003
On Fri, 2003-03-14 at 16:19, John Machin wrote:
> Chad Netzer <cnetzer at mail.arc.nasa.gov> wrote in message news:<mailman.1047603262.3191.python-list at python.org>...
> > def sectors(x):
> > if ((x % 512) != 0):
> > x = x + 1
> > return sectors(x)
> > else:
> > return x
> > BTW - There are better methods of finding the next larger power of two.
> (2) "power of 2" seems totally irrelevant.
Oops, you are right. The task was to find the next higher multiple of
512 (as you stated).
> Try this:
> def round_to_higher_mult_of_512(x):
> return ((x + 511L) // 512L) * x
> # 'L' just in case rounded-up file size >= 2GB
I'll suggest this instead:
# Will automatically promote to long int in python 2.2.x
return (x//512 + 1) * 512
Bay Area Python Interest Group - http://www.baypiggies.net/
(any opinion expressed is my own and not NASA's or my employer's)
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