Setting http proxy programmatically

Davor Cengija dcengija_remove_ at inet.hr
Wed Mar 19 13:06:22 CET 2003


Davor Cengija wrote:
> Basically, I need to set http proxy within my program. I use
> urllib2.urlopen(url, data) to submit some form data and it works fine when
> having no proxy, or when http_proxy environment variable is set, but the
> program will be run behind a firewall which forces proxy.
> 
[snip] 
> Where I should instantiate ProxyHandler and/or Request and how can I force
> urllib2.urlopen() to use it?
> 

Eh.. this is what happens when you're so new that you don't even know where 
to start investigating :-)

However, the solution I fould doesn't work.

Here's what I have now:

    def doSubmit(self, email):
        self.addEmail(email)
        preparedUrl = self.url + "?%s" % self.params
        log(preparedUrl)
        proxy = urllib2.ProxyHandler({"http" : http_proxy})
        opener = urllib2.build_opener(proxy)
        urllib2.install_opener(opener)        
        return urllib2.urlopen(preparedUrl).info()

The program simply ignores the proxy setting and doesn't even try to 
connect to it (I can read the proxy's logs). Even more, when 
urllib2.install_opener(opener) is called, program ignores the http_proxy 
environment variable as well.

The error I'm getting is:

<urlopen error (-3, 'Temporary failure in name resolution')>

while I expect

HTTP Error 404: WWWOFFLE Will Get

which happens when urllib2.install_opener(opener) is commented out and 
http_proxy environment variable is set.

Thanks!
-- 
Davor Cengija, dcengija_remove_ at inet.hr




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