fredrik at pythonware.com
Sat Nov 22 15:59:59 CET 2003
> > I would like to know if executing:
> > c = compile('a=5\nprint a','<string>','exec')
> > on a Linux box, then pickling+beaming the result on a Windows box, will give
> > me the expecting result:
> > >>> exec(c)
> > 5
> > In other words, does 'compile()' generate platform-dependent code?
> If you mean "marshal" instead of "pickle", and use the same (major)
> Python version on both ends, then yes.
to make sure both sites are using the same byte code revision,
check the imp.get_magic() string.
something like this should work:
code = compile(...)
data = imp.get_magic() + marshal.dumps(code)
magic = imp.get_magic()
if not data.startswith(magic):
raise ValueError("cannot run this bytecode")
code = marshal.loads(data[len(magic):])
(len(magic) is currently 4, and will probably remain so for the
foreseeable 2.X future, but one never knows what happens in
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