trouble with regex with escaped metachars (URGENT please O:-)

[Roel Mathys]

Fernando Rodriguez wrote:
> On Thu, 20 Nov 2003 16:13:19 GMT, Roel Mathys <rm at rm.net> wrote:
> 
> 
> 
>>>I get this error:
>>>Traceback (most recent call last):
>>>  File "<pyshell#38>", line 1, in -toplevel-
>>>    pat.sub(s,cts)
>>>  File "C:\ARCHIV~1\python23\Lib\sre.py", line 257, in _subx
>>>    template = _compile_repl(template, pattern)
>>>  File "C:\ARCHIV~1\python23\Lib\sre.py", line 244, in _compile_repl
>>>    raise error, v # invalid expression
>>>error: bogus escape (end of line)
>>>
>>>What on earth is this? O:-)
>>
>>it's the value of "value" that gives trouble (ending with a "bogus" \ 
>>followed by an (invisible) end-of-line.
>>This little patch will do the trick, and apparantly
> 
> 
> But the final backslash is escaped, it shouldn't be a problem... :-(
> 
> 

like I said, don't know
even stranger, with this value it does work

=> value = "c:\\apps\\whatever\\\\"

but like I showed in the previous post, you don't really need a regex 
for this.

eg:

def substitute2( name , value , cts ) :
     ucts = cts.upper()
     uname = name.upper()
     parts = ucts.split( r'$<' + uname + '>' )
     if len( parts ) != 2 :
         raise 'Something'
     return value.join( [ cts[:len(parts[0])] , cts[-len(parts[1]):]])

will do the job just as fine

bye,
rm