Time-date as an integer

[Roel Schroeven]

Charles Hixson wrote:
> This is a concept, not a finished program, and an extract from a class 
> at that...so forgive any illegalities, but:
> import    datetime;
>  def    calcNodeId(self):
>    t    =    datetime.utcnow()
>    val    =    t.year *    133920000000    +          #    12 months
>                    t.month    *    11160000000    +    #    31 days
>                    t.hour    *    3600000000    +         #    60 minutes
>                    t.minute    *    60000000    +         #    60 seconds
>                    t.second    *    1000000    +    t.microsecond
>    if    val <=    self._dTime:
>      val    =    self._dTime + 1
>    self._dTime    =    val
>    return    val
> 
> This is the best that I've been able to come up with in getting a 
> date-time as an integer.  It feels like one of the time or date 
> libraries should have a better solution, but if so, I haven't found it.  
> Can anyone suggest a better approach?

int(time.time())

That gives only second precision, though.

Calculations such as the one above can be simplified somewhat by grouping:

val = t.microsecond +
       1000000 * (t.second +
                  60 * (t.minute +
                        60 * (t.hour +
                              24 * (t.day +    # (you forgot this one)
                                    31 * (t.month +
                                          12 * year)))))

Or with less indentation, I used it here just to make the grouping clear.

-- 
"Codito ergo sum"
Roel Schroeven