Help with trapping an exception

pythos pythos
Tue Aug 24 03:05:15 CEST 2004

I have a piece of code like this:

	some code
	print >> sys.stderr, "error: ", sys.exc_info()

When an exception is thrown from the code, what I see on the console is this:

error: (<class exceptions.NameError at 0x01E7A378>, <exceptions.NameError
instance at 0x09752C50>, <traceback object at 0x096A1408>)

I had a lot of trouble figuring out what was causing the NameError.  I finally
figured it out by removing the "try" and "except" statements so that my code
didn't catch any exceptions.  When I did that, I saw the following on my

Traceback (most recent call last):
  File "c:\Documents and Settings\xxxxx\rot.PspScript", line 79, in Do
    os.path.walk(baseDirectory, ProcessDirectory, Environment)
  File "c:\Program Files\xxxxxx\Python Libraries\lib\", line 318, in
    func(arg, top, names)
  File "c:\Documents and Settings\xxxxx\rot.PspScript", line 36, in
    App.Do(Environment, 'FileOpen', {
NameError: global name 'Environment' is not defined

Now that was much more helpful.  Once I knew that 'Environment' was not
defined, I easily figured out the problem.  But I need to use "try" and
"except" to catch the exception, otherwise my program will end abruptly
without finishing.  So how can I see the "NameError: global name 'Environment'
is not defined" message in the "except" section of my code?  A call to
sys.exc_info() doesn't show it.  Is there another function I can use?  Thanks.

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