Find out the file name of a module from inside the module?

Michael Hudson mwh at python.net
Mon Aug 9 15:39:17 CEST 2004


Andreas Neudecker <a.neudecker at uni-bonn.de> writes:

> Hi.
> 
> I know you can read the filename of a program as sys.argv[0]. But what
> about modules? Is there a similar way to find out the file name of a
> module (called by some other module or program) from inside this
> module?

Uh, your question makes my head spin a bit, but is __file__ what you
want?

>>> import os
>>> os.__file__
'/usr/lib/python2.2/os.pyc'

Cheers,
mwh

-- 
  Of the four project development variables - scope, cost, time and
  quality - quality isn't really a free variable.  The only possible
  values are "excellent" and "insanely excellent", depending on
  whether lives are at stake.              -- Kent Beck, XP Explained



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