Find out the file name of a module from inside the module?
tismer at stackless.com
Mon Aug 9 15:41:12 CEST 2004
Andreas Neudecker wrote:
> I know you can read the filename of a program as sys.argv. But what
> about modules? Is there a similar way to find out the file name of a
> module (called by some other module or program) from inside this module?
If your modules knows that it is a module, it can inspect its
You can find out whether you have been imported by testing
whether there is a __file__ attribute, otherwise you are
probably executed, and there is no name available.
fname = __file__
fname = "?"
In cases where you absolutely need a file name, and if you know
that you are also used as a module, you can of course import
yourself, in order to get the file name. This implies the need
to know your module name, which doesn't make things so much better:
# assuming this is MyModule
fname = MyModule.__file__
Or even shorter:
from MyModule import __file__ as fname
ciao - chris
Christian Tismer :^) <mailto:tismer at stackless.com>
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