create lowercase strings in lists - was: (No subject)

Mark Devine markdevine at
Thu Dec 16 23:21:22 CET 2004

Actually what I want is element 'class-map match-all cmap1' from list 1 to match 'class-map cmap1 (match-all)' or 'class-map cmap1 mark match-all done' in list 2 but not to match 'class-map cmap1'.
Each element in both lists have multiple words in them. If all the words of any element of the first list appear in any order within any element of the second list I want a match but if any of the words are missing then there is no match. There are far more elements in list 2 than in list 1.

Steve Holden <steve at> wrote:

> Mark Devine wrote:
> > Sorry for not putting a subject in the last e-mail. The function lower suited my case exactly. Here however is my main problem:
> > Given that my new list is :
> > [class-map match-all cmap1', 'match ip any', 'class-map match-any cmap2', 'match any', 'policy-map policy1', 'class cmap1', 'policy-map policy2', 'service-policy policy1', 'class cmap2']
> > 
> > Each element in my new list could appear in any order together within another larger list (list1) and I want to count how many matches occur. For example the larger list could have an element 'class-map cmap2 (match any)' and I want to match that but if only 'class-map match-any' or 'class-map cmap2' appears I don't want it to match. 
> > 
> > Can anybody help?
> > Is my problem clearly stated?
> > 
> Well, let's see: you'd like to know which strings occur in both lists, 
> right?
> You might like to look at the "Efficient grep using Python?" thread for 
>   suggestions. My favorite would be:
> .>>> lst1 = ["ab", "ac", "ba", "bb", "bc"]
> .>>> lst2 = ["ac", "ab", "bd", "cb", "bb"]
> .>>> dct1 = dict.fromkeys(lst1)
> .>>> [x for x in lst2 if x not in dct1]
> ['bd', 'cb']
> .>>> [x for x in lst2 if x in dct1]
> ['ac', 'ab', 'bb']
> regards
>   Steve
> -- 
> Steve Holden     
> Python Web Programming
> Holden Web LLC      +1 703 861 4237  +1 800 494 3119
> -- 

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