More baby squeaking - iterators in a class
tjreedy at udel.edu
Fri Dec 31 17:17:29 CET 2004
"Bulba!" <bulba at bulba.com> wrote in message
news:bvaat0pq3ruq789dfl4fpe0mg4jd2of2qn at 4ax.com...
> Thanks to everyone for their responses, but it still doesn't work re
> returning next() method:
> class R3:
> def __init__(self, d):
> def __iter__(self):
> d,i = self.d, self.i
> while i>0:
> yield d[i]
This is the wrong test for what I and some others thought you were asking.
The requirement for p to be an *iterable* and useable in code such as 'for
i in p' is that iter(p), not p itself, have a .next method, and iter(p)
will. Try ip=iter(p) followed by ip.next and ip.next() instead.
If, for whatever reason, you instead want p to actually be an *iterator*
with a .next (or .getitem) method, then, of course, you have to actually
give it a .next (or .getitem) method.
Terry J. Reedy
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