question on regular expressions
mfuhr at fuhr.org
Fri Dec 3 19:31:18 CET 2004
Darren Dale <dd55 at cornell.edu> writes:
> I'm stuck. I'm trying to make this:
> (no linebreaks) look like this:
> my regular expression abilities are dismal.
This works for the example string you gave:
newstring = re.sub(r'[^,]*%5[Cc]', './', examplestring)
This replaces all instances of zero or more non-commas that are
followed by '%5C' or '%5c' with './'. Greediness causes the pattern
to replace everything up to the last '%5C' before a comma or the
end of the string.
Regular expressions aren't the only way to do what you want. Python
has standard modules for parsing URLs and file paths -- take a look
at urlparse, urllib/urllib2, and os.path.
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