Why would I use inspect.isclass()?
itsme at yahoo.com
Thu Dec 30 04:40:49 CET 2004
Thanks for the response. Please see comment below.
"Nicolas Fleury" <nid_oizo at yahoo.com_removethe_> wrote in message
news:asKAd.30749$%k.2293869 at weber.videotron.net...
> > an_instance=Abc()
> > But what good is that? Of course I know Abc is a class, why would I
> > inspect it so that it would tell me what I already know?
> Well, for no reason in that case. For the same reason you would not
> call isinstance(an_instance, Abc) if you already know an_instance is an
> instance of Abc.
> > def Hello(self, some_class):
> > # since I don't know if the argument passed down *is* a class or
> > would:
> > if inspect.isclass(some_class)==True:
> > ...
> > return
> > ###
> > But that obviously isn't what isclass is for. What should I use?
> Well, it's obviously what isclass is for;) (By the way, you would be
> better not compare your conditions with True, unless it's really what
> you want).
But inspect.isclass(some_class) returns a False no matter what. That's why
I am confused.
The only way I get isclass to return True is inspect.isclass(Abc) in my
> I guess another example would be an assert on the type of argument:
> def foo(someClass):
> assert inspect.isclass(someClass)
> # rest of code
But that would always fail! (I just tried it).
> This way errors on types are handled at the beginning and at the same
> time the code it documenting itself. The function could also be useful
> in cases where you do some C++-like overloading mechanism. Anyway,
> isclass, like iscallable, are functions that are not used often, but you
> still might need them.
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