nun at example.com
Wed Dec 1 17:43:28 CET 2004
On Wed, 1 Dec 2004 07:48:24 -0600, Philippe C. Martin
<philippecmartin at sbcglobal.net> wrote:
> I realize this is more a regexp question than a python question, but
> maybe one
> of the re object could help me:
> I have wish to know how to _no_ match:
> This is but an example of the data I handle:
> xx xx xx xx xx xx xx [yy yy yy yy yy yy yy] (zz zz zz zz)
> I currently can retrieve the three group of logical data blocks with:
> l_str = 'xx xx xx xx xx xx xx [yy yy yy yy yy yy yy] (zz zz zz zz)'
> p = re.compile(r'([a-f-0-9\s]*) (\[[a-f-0-9\s]*\])
> (\([a-f-0-9\s]*\))',re.IGNORECASE) #OK
> g = p.search(l_str)
> What I would rather do is.
> "get the data block that is _not_ between brackets or parenthesis i.e;
> 'xx xx
> xx xx xx xx xx' knowing that the intial string could be:
> [yy yy yy yy yy yy yy] xx xx xx xx xx xx xx (zz zz zz zz)
> Any clue ?
regexps seem an overkill for the task at hand.
If data is really as simple as you suggest, you can try the following:
>>> s = 'xx [y y] (z z)'
>>> s = s[:s.index('(')] + s[s.index(')')+1:]
'xx [y y] '
>>> s = s[:s.index('[')] + s[s.index(']')+1:]
s = s[:s.index('(')] + s[s.index(')'):]
s = s[:s.index('[')] + s[s.index(']')+1:]
s = s.strip()
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