newbie question
Doug Holton
insert at spam.here
Sun Dec 19 18:55:09 EST 2004
David Wurmfeld wrote:
> I am new to python; any insight on the following would be appreciated, even
> if it is the admonition to RTFM (as long as you can direct me to a relevant
> FM)
>
> Is there a standard approach to enumerated types? I could create a
> dictionary with a linear set of keys, but isn't this overkill? There is
> afterall a "True" and "False" enumeration for Boolean.
To actually answer your question, no, there is no standard for enums in
python. There are custom hacks for it that you can search for.
Boo, a programming language that is virtually identical to python, does
have standard enums:
enum Color:
Red
Green
Blue
See http://boo.codehaus.org/
In fact, since not many seem to be aware of its existence, I encourage
everyone here to check out boo as an alternative to python.
> Is there a way to ignore case in string comparisons? I want 'Oranges' to
> equal 'oranges' when using the evaluation operator (==). I don't care about
> string inequalities (<, >)
No, not with the == operator, unless you use:
s1.lower() == s2.lower()
Visual Basic is the only language I am aware of that has
case-insensitive strings.
> Finally, (for now at least) consider the following list.
>
> myList = [apple, 13, plum, cherry, 'Spam', tomato, 3.35]
>
> Exactly how does the "for x in myList" work?
> If the list is a heterogeneous list of disparate types, the == operator
> works fine, independent of type.
> For example, (if x == 'spam') evaluates as false if the item in the list is
> an integer. But if I try to do this: (if x.__abs()__) throws an exception if
> x "pulls" a non integer from the list. Wouldn't you think that an iterative
> would have the "sense" to understand that in this limited scope if a method
> didn't apply to the iterator just "fail" (i.e. evaluate to False) the
> evaluation and move along? Do I have to manually interrogate each iteration
> for the proper type before I test?
> Think about it; the interpreter has to evaluate disparate types for
> equality. How exactly does the it "know" that for this iteration, x is an
> integer, and the evaluation (if x == 'spam') is False, and doesn't throw an
> exception for a type mismatch?
Because python is a strongly typed. If you want to perform a type
specific operation like abs() or string.lower(), but the object's type
may not be the right type, then you have to check its type first.
In boo, we have an "isa" operator for this purpose:
if x isa string:
....
or:
for item in myList:
given typeof(item):
when string:
print item.ToLower()
when int:
print Math.Abs(item)
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