Integer math question

Sean Ross sross at connectmail.carleton.ca
Sat Jan 3 20:57:44 CET 2004


"Rainer Deyke" <rainerd at eldwood.com> wrote in message
news:kTEJb.724242$HS4.5376202 at attbi_s01...
> Sean Ross wrote:
> > a = bq + r       and  0<=r<b       [1]
>
> But 0 <= r < b is a contradiction when b < 0.
>

Right.  But, the division algorithm states "Let a,b be integers with b>0"
(which I mentioned in that post).







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