delta time = time stop - time start

engsol engsolnorm at ipns.com
Mon Jan 26 07:08:05 CET 2004


I'm using Python to parse a bunch of s/w test files and make csv files for later report generation by MS ACCESS....(my boss
loves the quick turn-around compared to C). Each log file may contain one or more 'sessions', and each session may contain
one or more 'nodes'.

Each session in the log has an ASCII  start and stop time, as does each node.
I have the basic parse part done for parameters, errors, etc., but noticed my routine for determining how long each
session/node took (delta time) was a bit repetitive, so decided to make a 'stand-alone' routine to handle this.

The time format from the log is in the format of:
hh:mm:ss
and is a string with leading zeros where appropiate. Date is never a factor. The longest "delta" is maybe 5 hours.

The routine I came up with is below, but seems a bit clunky.
Is there a better way of doing this? I think it relies too much on integers rounding off in the proper direction, a la
d_time_hr = d_time / 3600 below.

Also, this will have to transition to Linux, if that makes a difference.

START CODE:

import string

def deltatime(start, stop):

    t_start = (string.atoi(start[0:2]) * 3600) + (string.atoi(start[3:5]) * 60) + string.atoi(start[6:8])
    t_stop  = (string.atoi(stop [0:2]) * 3600) + (string.atoi(stop [3:5]) * 60) + string.atoi(stop [6:8])

    if t_start < t_stop:
        d_time = t_stop - t_start
    else:
        d_time = (86400 - t_start) + t_stop

    d_time_hr  =  d_time / 3600
    d_time_min = (d_time - d_time_hr * 3600) / 60
    d_time_sec = (d_time - d_time_hr * 3600) - (d_time_min * 60)

    return str(d_time_hr) + 'hr ' + str(d_time_min) + 'min ' + str(d_time_sec) + 'sec'

END CODE

TRY IT

print deltatime('23:45:00', '02:55:03')

RETURNS

3hr 10min 3sec

Thanks.....Norm
PS Please reply via email (engsolnorm at hotmail.com) until my ISP gets fixed.





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