Escaping slashes (double backslash plague)

Aloysio Figueiredo xpythonist at yahoo.com.br
Mon Jan 19 13:43:01 CET 2004


I need to replace every ocurrence of '/' in s by '\/'
in order to create a file named s. My first attempt
was:

s = '\/'.join(s.split('/'))

but it doesn't work:

>>> s = 'a/b'
>>> s = '\/'.join(s.split('/'))
>>> s
'a\\/b'
>>> repr(s)
"'a\\\\/b'"
>>>

'\/'.join() escapes the backslashes and I don't know
why. 

Any help?

Aloysio Figueiredo

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