csv - how to parse a string, not a file?

John Lenton jlenton at gmail.com
Sun Jul 11 01:46:41 CEST 2004


On Sat, 10 Jul 2004 19:50:25 GMT, Alex Hunsley
<lard at tardis.ed.ac.molar.uk> wrote:
> John Lenton wrote:
> 
> > On Sat, 10 Jul 2004 19:21:23 GMT, Alex Hunsley
> > <lard at tardis.ed.ac.molar.uk> wrote:
> >
> >>I've using the csv module to parse a string, not a file.
> >>So how do I make a string look like a file so I can call csv.reader()
> >>with it?
> >>
> >>An an example, I'd like to call something like:
> >>
> >>csvReader = csv.reader("1,2,3,4")
> >>
> >>.. but this direct attempt won't work as it expects a file or a handle...
> >
> >
> > what is cStringIO?
> >
> 
> I'm not sure, but if you google there are answers:
> 
> http://www.google.com/search?hl=en&ie=UTF-8&q=cStringIO&btnG=Google+Search

sorry; I should stop giving answers as questions.

-- 
John Lenton (jlenton at gmail.com) -- Random fortune:
bash: fortune: command not found



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