ville at spammers.com
Thu Jul 8 14:24:46 CEST 2004
>>>>> "Jakub" == Jakub Fast <kfast at poczta.onet.pl> writes:
>> Currying: lambda x,y : f(x,y,1,2)
Jakub> lambda x: lambda y: f(x,y,1,2)?
Jakub> but then
Jakub> (lambda x: lambda y: f(x,y,1,2))(3, 4)
Jakub> won't work.
Of course it won't. It's the difference b/w taking 1 and 2 parameters.
(lambda x: lambda y: f(x,y,1,2))(3)(4)
I guess you will see that e.g in haskell
f 1 2
does exactly this:
((f 1) 2 )
Jakub> so much for currying?
Ville Vainio http://tinyurl.com/2prnb
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