Passing parameters using **kargs
Terry Reedy
tjreedy at udel.edu
Tue Jun 8 18:23:52 EDT 2004
"Aahz" <aahz at pythoncraft.com> wrote in message
news:ca50ga$hhl$1 at panix1.panix.com...
> >_f_orig = f
> >def f(*largs, **kargs):
> > print 'f called with' largs, 'and', kargs
> > f(*largs, **kargs)
>
> You mean
>
> _f_orig(*largs, **kargs)
Of course. Silly 'rushing out the door' mistake.
> I prefer this version:
>
> def debugParams(func):
> def debugger(*args, **kwargs):
> for arg in args:
> print type(arg), arg
> for name in kwargs:
> value = kwargs[name]
> print name, type(value), value
> return func(*args, **kwargs)
> return debugger
>
> f = debugParams(f)
So do I, for its elaboration, factorization, and closure. I am saving it.
Terry J. Reedy
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