string to object?

[Guy Robinson]

Peter and Larry,

To clarify things more (as I should have done yesterday):

incompatible signatures are not what I want and I do understand I need 
to instance the class first so yes

class foo:
	def method1(self, *args):
		return 'one'
	def method2(self, *args):
		return 'two'
ifoo=foo()

is more like it. I have a number of classes with methods. For various 
reasons the class.method to run is only available as a string. The 
arguments arrive independently. So the question is how can I convert a 
string to a class.method object for instancing?

Pseudo python:

s = 'foo.method1'
arg = []
sclass,smethod = string2class(s)
isclass = sclass.smethod(arg)

TIA,

Guy

> This does what you asked for, but I suspect
> it isn't the best way to accomplish what you
> want to do (just guessing).  You can't call
> a class, you must call an instance of a class
> (e.g. ifoo below).
> 
> class foo:
>     def method1(self, *args):
>         return 'one'
>     def method2(self, *args):
>         return 'two'
> 
> ifoo=foo()
> li=[ifoo.method1, ifoo.method2]
> 
> args=(1,)
> for l in li:
>     print apply(l, args)
> 
> 
> HTH,
> Larry Bates
> Syscon, Inc.
> 
> 
> "Guy Robinson" <guy at NOSPAM.r-e-d.co.nz> wrote in message
> news:caccdm$fd$1 at lust.ihug.co.nz...
> 
>>Hello,
>>
>>I have a class:
>>
>>class foo:
>>
>>def method1(self,args):
>>return 'one'
>>def method2(self):
>>return 'two'
>>
>>and I have a series of strings li = ['foo.method1','foo.method2']
>>
>>is there anyway I can do this?:
>>
>>for l in li:
>>print l(args)
>>
>>getattr('foo','method1') didn't work as 'foo' is invalid.
>>
>>Any suggestions appreciated.
>>
>>Guy
> 
> 
>