mutable default parameter problem [Prothon]

Christos TZOTZIOY Georgiou tzot at sil-tec.gr
Thu Jun 17 13:57:27 CEST 2004


On Wed, 16 Jun 2004 21:41:07 -0700, rumours say that "Mark Hahn"
<mark at prothon.org> might have written:

>"Dave Brueck" <dave at pythonapocrypha.com> wrote
>
>> > > I like more as an example:
>> > >
>> > >    >>> def foo(x):
>> > >    ...   if not hasattr(foo,'list'):
>> > >    ...     foo.list = []
>> > >    ...   foo.list.append(x)
>> > >    ...   print foo.list
>> >
>> > In Prothon:
>> >
>> >     def foo(x):
>> >             print foo.list.append!(x)
>> >     foo.list = []
>> >
>> > (Sorry. I couldn't resist bragging.)
>>
>> About what?
>
>Is there an echo in here?  :-)

Probably not.  Given the python version:

    def foo(x):
        foo.list.append(x)
        print foo.list
    foo.list = []

Dave's question is legitimate.  Are you bragging about the two lines
combined into one?
-- 
TZOTZIOY, I speak England very best,
"I have a cunning plan, m'lord" --Sean Bean as Odysseus/Ulysses



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