Replace text with value form dictionary (regexp)

Jean-Pierre Bergamin james at ractive.ch
Wed Mar 3 15:32:57 CET 2004


Jean-Pierre Bergamin wrote:

> I want to implement a small templating system where values in angle
> brackets should be replaced by the corresponding dicitionary value
> ("foo {x} bar" -> "foo 10 bar");
>
>>>> d = {}
>>>> d["x"] = 10
>>>> p = re.compile('{ ( [^}]* ) }', re.VERBOSE)
>>>> p.sub(r'd["\1"]','foo {x} bar')
> 'foo d["x"] bar'
>
> How can I now put the actual value of d["x"] into the string 'foo
> d["x"] bar'?

I have this solution now:
    import re

    d = {}
    d["x"] = 10
    d["y"] = "20"

    def repl(matchobj):
     return str(d[matchobj.group(2)])

    p = re.compile('({ ([^}]*) })', re.VERBOSE)
    print p.sub(repl, 'foo {x} bar {y} gugu')

Any better solutions?


Regards

James





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