v # invalid expression ?

Anthony Liu antonyliu2002 at yahoo.com
Thu Mar 11 10:16:03 CET 2004


I am trying to split a string like so:

re.split(',|。|、|!|:|,|?|“|”|)|(|;',
my_string)

Python complains like so:

Traceback (most recent call last):
  File "C:\Python23\codes\regextest.py", line 27, in
-toplevel-
    ultimate =
re.split(',|。|、|!|:|,|?|“|”|)|(|;',
ch[0])
  File "c:\python23\lib\sre.py", line 156, in split
    return _compile(pattern, 0).split(string,
maxsplit)
  File "c:\python23\lib\sre.py", line 229, in _compile
    raise error, v # invalid expression
error: nothing to repeat

Does this mean that the regular expression I pass to
the split function is not valid?

That expression is just like ',|)|#|!', that is, an
or-ed list of punctuations. Then why invalid?



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