Iterating Dictionaries in a Function

[Ryan Paul]

On Fri, 07 May 2004 18:23:10 -0700, Thinker wrote:

> I could not get this simple code work. I am guessing that there is a
> bug
> in the Python dictionary iterator.
>  
> def findx(st):
>         d = {'a': 1, 'rty': 4, 'er': 2}
>         for item in d.keys(): 
>                 print item    
>                 if cmp(item.upper(),st.upper()) == 0:
>                         print d[item] 
>                         return d[item]
>                 else: 
>                         return st
>                          
>                          
> When I call:             
> findx('a')               
> it finds the key. But when I call:
> findx('er')              
> it does not find anything since it does not iterate; it just checks
> the first item in the dictionary.
> 
> Does anyone see where the bug is?

its never going to make it past the first item, because you tell it to
return.

maybe you meant...?:

def findx(st):
  d = {'a': 1, 'rty': 4, 'er': 2}
  for item in d.keys():
    print item    
    if item.upper() == st.upper():
      print d[item]
      return d[item]
  return st

either way, looks like you should spend some time with the documentation.