function causing core dump

[Peter Otten]

Xaver Hinterhuber wrote:

> Hello pythonistas,
> 
> I build a function with the following code segment:
> 
>     codeObject = new.code(
>       0, # argcount
>       0, # nlocals
>       0, # stacksize
>       0, # flags
>       codeString, # code
>       (), # consts
>       (), # names
>       (), # varnames
>       'content', # filename
>       'content', # name
>       3, # first line number
>       codeString # lnotab
>       )
>     f = new.function(codeObject, dict, 'f')
>     f()
> 
> Everything runs fine, until the function is called with f().
> When python tries to execute f(), the core dump happens.
> I don't have any clue why python core dumps.
> The codeString is nothing complex, its a one-liner.
> Could you plz give me some tips what I have to do?
> 
> With kind regards
> Xaver Hinterhuber

The easiest approach is probably to start with an attribute set known to be
good:

>>> def f(): pass
...
>>> code = f.func_code
>>> names = dir(code)
>>> names.sort()
>>> for name in names:
...     if not name.startswith("_"):
...             print "%s=%r" % (name, getattr(code, name))
...
co_argcount=0
co_cellvars=()
co_code='d\x00\x00S'
co_consts=(None,)
co_filename='<stdin>'
co_firstlineno=1
co_flags=67
co_freevars=()
co_lnotab=''
co_name='f'
co_names=()
co_nlocals=0
co_stacksize=1
co_varnames=()
>>>

and change the values until you get a core dump - again.

Peter