is int(round(val)) safe?

[Steven Bethard]

Peter Hansen wrote:
> Since round() returns an integer

Just to clarify in case anyone else misreads this, I belive the intent 
here was to say that round(f) -- that is, round with only a single 
argument -- returns a floating point number with no fractional component 
after the decimal point.  The result is still a float, not an int though:

 >>> round(3.14159265359)
3.0
 >>> round(3.14159265359, 2)
3.1400000000000001

I think the intent was clear from the rest of the post, but I figured it 
wouldn't hurt to clarify this for any newbies who misread it like I did.

Steve