how to check if URL cannot be opened
jmeile at hotmail.com
Wed Oct 27 21:05:14 CEST 2004
> Im new to python. So I was hoping someone could provide the following.
> How would I go about checking if a user can be opened. For example if
> user provides www.x.com, how would I check if there is such a url?
> What methods would I need to invoke?
This is the code I use with python greater than 2.3.3:
def checkUrl(url, timeout=5, SSL=0):
"""Checks an url for a python version greater
except (urllib2.HTTPError, urllib2.URLError,
Please note that I use the setdefaulttimeout method of the module socket
because sometimes, specially if you type invalid ssl urls, the main
thread will take a long time till you see an answer. With the timeout,
it will wait for 5 seconds, then it will return. I also use the urllib2
because its urlopen method is better than the original of urllib: Some
webservers like zope, return an error page when an url isn't found; with
urllib.urlopen, this page will be considered as a normal page. On the
other hand, the urllib2.urlopen will raise an exception.
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