Re-executing the code object from a class 'declaration'
carribeiro at gmail.com
Wed Oct 6 19:14:16 CEST 2004
On Wed, 6 Oct 2004 18:49:58 +0200, Alex Martelli <aleaxit at yahoo.com> wrote:
> Carlos Ribeiro <carribeiro at gmail.com> wrote:
> > > module and place a dis.dis(dct['my_code']) in the metaclass's __new__
> > > and you'll see that basically MyClass.re_execute isn't very different
> > > from a reload of the module. Isn't that a _bit_ too much in general?
> > (repeating to myself: dis is your friend. dis is your friend).
> If you're hacking at this level, it sure is;-).
> > done a few more tests. I found a way to find the correct code object
> > for the _body_ of the class statement (or at least I think so), but
> Good -- as I said I think it can be even more reliably found from inside
> the classbody itself, but, no big deal.
> > exec klass.my_code
> Ah, this is your problem -- that's not what you want to do now.
> > problem is that the code block that is found refers to the class
> > _body_ only. Checking dis.dis() helps to understand it:
> Exactly: it's what builds the dict you want to pass to the metaclass
> (once you wrap it into a new.function, as I mentioned).
> > There is not a single code block that does all the tasks related to
> > the class statement, and only it. In fact, there are two different
> > code objects to choose from, and neither really solves the problem.
> Not by itself, but add some code and you'll be fine.
> 1. You need to build an f = new.function(klass.my_code, globals()) in
> your classmethod that now erroneously does the exec above quoted (you
> could in fact do this in the metaclass, save the new function rather
> than the code object -- get the right globals via inspect).
That's the part that I was missing. It looks less 'hackish' than I had
expect. I was really afraid that I would need to manage bytecode-level
hacks myself. I am not as concerned about getting the right globals,
though -- it's good enough if I'm able to supply whatever globals I
need upon calling, I think (unless I'm _really_ missing something).
> 2. you need to obtain the needed dict, that's just d = f() in your
There is still a question, but I think I already know the anwswer :-)
If the class *has* a base class, it has to be passed as a parameter. I
assume that i can simply call it like this: d=f(bases); or instead,
that I can fill the argdefs in the new.function call. I'll try it
> 3. you can now call your metaclass with the appropriate bases and name:
> klas = self.__class__ # or cls if this is a classmethod;-)
> return type(klas)(klas.__name__, klas.__bases__, d)
> voila, you're there. This is all coded to minimize the need to have
> this method located in a specific class -- as I said I think you
> probably want to have this stuff in the metaclass (if you have a
> metaclass at all), but, whatever.
Tehre are two reasons to do it in a metaclass: first, I tested it and
it works (of sorts), while for some reason it wont work for a
non-metaclasses enabled class. Also, because in this scenario there
are other things that I already need to check, and a metaclass does it
> This is basically just mimicking what Python itself does (check the
> dis.dis for a class statement as a starter): get the class body's code
> object, build a function from it, call the function (it returns its
> locals() as the result -- that 'return' is of course in the class body's
> code object, and dis.dis shows that...), and that's how you get the
> classdict on the stack. Add name and bases, call the metaclass, and
> Bob's your uncle...
For now, I think I'll just be using the class-inside-a-def idiom. But
I'm still working around some design issues, and if the templating
mechanism gets in the final production code (it's only one of a few
competing designs), I'll surely try it again.
Consultoria em Projetos
mail: carribeiro at gmail.com
mail: carribeiro at yahoo.com
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