Calling a constructor by reference

Russell Blau russblau at hotmail.com
Thu Oct 7 15:59:54 CEST 2004


"Russell Blau" <russblau at hotmail.com> wrote in message
news:2skvurF1mh1b5U1 at uni-berlin.de...
> Hint:  what do you see if you run the following function?
>
> >>> def show_args(type, *args):
>         print args
>
> >>> show_args()

D'oh! You see an exception, of course!  That last line should be
show_args(X), where X is some object you have already created.

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