os.popen3 with windows; help?
Patrick L. Nolan
pln at cosmic.stanford.edu
Tue Oct 26 18:46:01 CEST 2004
Lad <export at hope.cz> wrote:
> "Russell E. Owen" <rowen at cesmail.net> wrote in message news:<rowen-1B99F3.15314025102004 at gnus01.u.washington.edu>...
>> I'm trying to launch an application from Python 2.3 on Windows. The
>> application is "ds9" (an image viewer), and is installed in C:\Program
>> On unix I just do:
>> and close the returned files and all is good. (I'm not trying to
>> communicate with the program via popen3 and so had been using
>> os.spawnlp, but that doesn't exist on Windows.)
>> On Windows os.popen3("ds9") does nothing, and the stderr returned from
>> os.popen3 has a message saying the program is unknown.
>> So I tried being specific:
>> os.popen3("C:\\Program Files\\ds9\\ds9")
>> This also fails and the program that is not found is "C:\Program",
>> suggesting that the space in "Program Files" is causing the problem. The
>> following failed in exactly the same way:
>> os.popen3("C:\\Program\ Files\\ds9\\ds9")
>> Any suggestions?
>> -- Russell
>> P.S. I installed the app using its Windows binary installer, which
>> unpacks a few files in C:\\Program files\. Windows doesn't seem to know
>> the program exists; it's not in the task bar, for example. But one can
>> double-click it to run it.
> I think the problem is in long name folder: Program Files. So, try
> Progra~1 instead of Program Files
An automatic way to accomplish this is
shortpath = win32api.GetShortPathName(path)
Also, I have found by bitter experience that ds9 is unable to open any
file whose path includes a space. Put your data files somewhere else.
* Patrick L. Nolan *
* W. W. Hansen Experimental Physics Laboratory (HEPL) *
* Stanford University *
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