Problem with a dictionary program....
Larry Bates
lbates at syscononline.com
Tue Sep 28 18:55:34 CEST 2004
Ling Lee wrote:
> Hello.
>
> I'm trying to write a small program that lets you put in a number as an
> integer and then it tells you the textuel representation of the number.
>
> Like if your input is 42, it will say four two.
>
> I found out that I have to make a dictionary like this: List = { 1:"one",
> 2:"two" and so on )
>
> and I have to use the raw_input method to get the number:
>
> indput : raw_input(" Tell me the number you want to transform to textuel
> representaion")
>
> The I have to transform the input to a string
> indput = str(indput)
>
> so that I can count how many decimals the number has, like 23 has 2 decimals
> and 3000 has 4 decimals.
>
> After I have gotten the lenght of the string, I will write a loop, that goes
> through the dictionary as many times as the lengt of the string, and the
> gives me the corresponding numbers, the numner 21 would go 2 times through
> the loop and give me the output two one
>
> Will one of you be so kind and tell me how I count the lengt of the indput
> number i was thinking on something like input.count[:] but that dosnt
> work...
>
> and how I make the loop.
>
> Im trying to understand dictionaries but have gotten a bit stuck...
>
> Thanks for all replies....
>
>
>
Here's an example of what you want:
""" Just run it, you'll see what it does.
This code is released into the public domain absolutely free by http://journyx.com
as long as you keep this comment on the document and all derivatives of it.
"""
def getfractionwords(num):
frac = num-int(num)
numstr = str(int(frac*100+.5))
if len(numstr) == 1:
numstr = '0'+numstr
fracstr = ' and ' + numstr + '/100'
return fracstr
def convertDigit(digit):
digits = ('', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven',
'Eight', 'Nine')
return digits[int(digit+.5)]
def breakintochunks(num):
(left,right) = breakintwo(num)
rv = [right]
while left > 999:
(left,right) = breakintwo(left)
rv.append(right)
rv.append(left)
rv.reverse()
return rv
def breakintwo(num):
leftpart = int(num/1000.0)+0.0
rightpart = 1000.0*(num/1000.0 - leftpart)
return (int(leftpart+.5),int(rightpart+.5))
def enties(num):
tens = ('','','Twenty' ,'Thirty', 'Forty', 'Fifty', 'Sixty',
'Seventy', 'Eighty', 'Ninety')
indx = int(num/10.0)
return tens[indx]
def convert2digit(num):
teens = ('Ten', 'Eleven', 'Twelve', 'Thirteen', 'Fourteen',
'Fifteen', 'Sixteen', 'Seventeen', 'Eighteen', 'Nineteen')
if num < 10:
return convertDigit(num)
if num <20:
return teens[num-10]
if num > 19:
tens = enties(num)
ones = convertDigit(10*(num/10.0-int(num/10.0)))
if ones:
rv= tens+'-'+ones
else:
rv=tens
return rv
def convert3digit(num):
threenum = str(num)
ln = len(threenum)
if ln==3 :
a= convertDigit(int(threenum[0]))
b= ' Hundred '
c= convert2digit(int(threenum[1:]))
return a+b+c
if ln<3 :
return convert2digit(int(threenum))
raise 'bad num',num
def num2words(num):
thousandchunks = breakintochunks(int(num))
rv = ' '
if num >= 1000000:
rv=rv+ convert3digit(thousandchunks[-3])+ ' Million '
if num >= 1000:
c3d= convert3digit(thousandchunks[-2])
if c3d:
rv=rv+ c3d+ ' Thousand '
rv = rv + convert3digit(thousandchunks[-1])+ getfractionwords(num)
return squishWhiteSpace(rv)
def squishWhiteSpace(strng):
""" Turn 2 spaces into one, and get rid of leading and trailing
spaces. """
import string,re
return string.strip(re.sub('[ \t\n]+', ' ', strng))
def main():
for i in range(1,111,7):
print i,num2words(i)
for i in (494.15, 414.90, 499.35, 400.98, 101.65, 110.94, \
139.85, 12349133.40, 2309033.75, 390313.41, 99390313.15, \
14908.05, 10008.49, 100008.00, 1000008.00, 100000008.00, \
14900.05, 10000.49, 100000.00, 1000000.00, 100000000.00, 8.49):
print i,num2words(i)
import whrandom
for i in range(33):
num = whrandom.randint(1,999999999) + whrandom.randint(1,99)/100.0
print num,num2words(num)
if __name__ == '__main__':
main()
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